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Free Academic Courses Online by Polly Blatherwater - Fri, 25 Jul 2014 03:21:10 EST ID:mSE/qEmh No.14247 Ignore Report Reply Quick Reply
File: 1406272870011.jpg -(27669B / 27.02KB, 593x457) Thumbnail displayed, click image for full size. 27669
I know there are at least a couple websites that offer free courses, but the only one I can remember is edX.org, which offers more career-specific courses and I'm looking for general stuff. I just want to take math from the ground up, starting with elementary algebra. /math/ where can I learn algebra online?
>>
Oliver Sodgekork - Fri, 25 Jul 2014 07:41:35 EST ID:Gw2IN3ba No.14248 Ignore Report Quick Reply
There really should be a sticky for this. It seems every other thread is asking for exactly what this site offers:

https://www.khanacademy.org/
>>
Charles Fudgefoot - Fri, 25 Jul 2014 17:56:08 EST ID:8PJ0nVdr No.14249 Ignore Report Quick Reply
http://patrickjmt.com/

For just math tutorials, Patrick is pretty good.
>>
Edwin Ponninglutch - Sun, 27 Jul 2014 05:44:13 EST ID:mSE/qEmh No.14251 Ignore Report Quick Reply
>>14247
Exactly what I was looking for thank you.
>>
Molly Wapperham - Wed, 13 Aug 2014 20:12:48 EST ID:ptieClIw No.14286 Ignore Report Quick Reply
MIT's opencourseware is also great when you get to higher level maths and math related subjects:
http://ocw.mit.edu/courses/find-by-topic/
Otherwise until you get to that point, khan academy.
>>
Archie Worthingfield - Sun, 07 Sep 2014 19:10:56 EST ID:xvgqavvT No.14355 Ignore Report Quick Reply
From the list/guide here: http://www.staff.science.uu.nl/~Gadda001/goodtheorist/primarymathematics.html I used this course on beginner's algebra: http://www.wtamu.edu/academic/anns/mps/math/mathlab/beg_algebra/ and also a few beginner's algebra books I found used in local bookstores when I wanted to refresh highschool math.

I then did Sheldon Axler's Precalculus, because it assumes you remember no trig .


A mathematical and artistic exercise: Higher Dimensional Beings by Cedric Gollergold - Thu, 10 Jul 2014 01:30:30 EST ID:yGgK6aCs No.14192 Ignore Report Reply Quick Reply
File: 1404970230302.jpg -(83646B / 81.69KB, 463x720) Thumbnail displayed, click image for full size. 83646
What I'm wondering is, what would it look like when a higher dimensional being moved through our dimensions? Obviously not a completely serious thread.
The artist/scientific portion of what I'm asking is: What would an intelligent life form look like in their n-dimensional glory?
The mathematical portion: I know you savages are capable of projecting n-dimensional structures into 3-dimensions. Has anything cool like this been done before? I'd be much more interested in projections with a time dimension.

The reason this interests me is that I'm fascinated with absolutely massive structures. The idea of a rapidly transforming organic structure popping in and out of existence is probably the most epic thing I can think of. The Halo games have been the most impressive things I've seen when it comes to showing you things with breathtaking scale. If the n-dimensional organic being was huge and a special effects company or game developer decided to take a swing at something like this, I'd be thrilled. I wouldn't mind you guys just talking about this instead of linking to media. I just don't hear this talked about very often.
10 posts and 1 images omitted. Click Reply to view.
>>
ASSHOLE JUNKIE - Wed, 06 Aug 2014 09:11:13 EST ID:otqnqn2l No.14269 Ignore Report Quick Reply
smoke DMT after reading flatterland

>your answer
>>
Hannah Blorryville - Fri, 08 Aug 2014 15:31:05 EST ID:/dt3ybWI No.14273 Ignore Report Quick Reply
Very Related OP: https://www.youtube.com/watch?v=N0WjV6MmCyM
>>
Nell Drinningfuck - Sun, 10 Aug 2014 18:01:14 EST ID:uspvjvJI No.14277 Ignore Report Quick Reply
>>14273
>This video is not available in your country.

Did I just get teleported to China? WTF?
>>
Nicholas Grimgold - Mon, 11 Aug 2014 19:45:31 EST ID:yGgK6aCs No.14278 Ignore Report Quick Reply
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>>14273
That's exactly where I got the idea, actually. I was just wondering if you guys could get crazy on me. As a physics student, we regard you math guys as people who just do wild shit for no reason that nobody ever asks for. We pretty much assume that you could answer most questions we have but as I've framed my questions as more open, I don't expect too much. I will certainly be reading flat land and flatter land and hopefully smoke DMT at some point in the process. Right now both of my threads are the top threads. This is a terribly slow board isn't it, you hard working motherfuckers?
>>
Hugh Brarringville - Wed, 13 Aug 2014 13:50:05 EST ID:Hs5ANTy/ No.14282 Ignore Report Quick Reply
>>14278
I'm just repeating myself here, but read Diaspora. Flatland and its sequels are good but if you already have some math background they'll all cover some pretty obvious stuff.

There are tons of ways for life to exist in a world with three spacial dimensions, and even more in four or more, assuming physical laws which work in those spaces. Do you have any more specific questions or do you just want to be entertained?

If people in a four dinensional world had cars, their wheels could have two degrees of freedom and still be 'flat' on one side. Their roads would approxomate three dimensional tubes kr parallelpipeds and the wheels would touch the road as a flat 2d shape instead of a line. There would be no left or right side of the road, but the road would probably still just connect two points in something approximating a thin line as they do in our world. I could go on and on but after a point it's really pretty boring.


Quick nit picky thing about Epsilon Delta Limits by Betsy Secklehid - Fri, 08 Aug 2014 08:51:33 EST ID:yGgK6aCs No.14271 Ignore Report Reply Quick Reply
File: 1407502293122.jpg -(16322B / 15.94KB, 300x319) Thumbnail displayed, click image for full size. 16322
I notice a few sources I've looked at specify that |x-a| is greater than 0, but never bother to do the same thing with |f(x)-L|. In my mind, if they do it with one and not the other, then I'm going to assume there is a reason for doing so and spend all sorts of time thinking about why the definition isn't symmetrical in this way. However, in my opinion specifying that the absolution value of anything is greater than zero seems completely redundant if we're beyond the discussion of what an absolute value is, so it seems to me that saying |x-a|< epsilon is complete. Is there a reason for specifying |x-a| is greater than zero or is this just a habit that's perpetuated?
3 posts omitted. Click Reply to view.
>>
Fanny Lightham - Sun, 10 Aug 2014 05:55:19 EST ID:qz3c7Bt+ No.14276 Ignore Report Quick Reply
You need |x-c| > 0 so that {x | |x-c| < delta} is a neighborhood. Whenever you show continuity of f at point c, you're demonstrating for a neighborhood V containing c, you'll get a neighborhood f(V) containing f(c).
>>
Fucking Gebberlock - Tue, 12 Aug 2014 17:31:37 EST ID:5HpdLBMD No.14280 Ignore Report Quick Reply
>>14271
Because then |f(x)-a| could equal zero. This can cause problems with definitions.
>>
Eliza Dissleway - Tue, 12 Aug 2014 20:48:44 EST ID:Gw2IN3ba No.14281 Ignore Report Quick Reply
>>14280
This. It seems so obvious now you mentioned it.

Disregard my previous answer OP; apparently I didn't have my thinking cap on when I replied.
>>
driven !FTPgBqDDy. - Wed, 13 Aug 2014 21:57:16 EST ID:y5R4M4OS No.14287 Ignore Report Quick Reply
>>14271
That's because there's a difference between the definitions for the limit of a sequence and the limit of a function. I don't have my analysis textbook but in a couple of days I can expand on this

Also the first thing inside your absolute value sign should be something that changes with respect to something else (e.g. xn) because it doesn't make sense to be continually comparing fixed quantities. So i'll use xn to represent a sequence x1, x2, x3, ...

|xn-a| can be zero, it's just not very interesting and doesn't occur for things like xn = 1/n (a is a fixed quantity so it can't cancel with 1/n).
>>
Ernest Gengerfield - Mon, 25 Aug 2014 00:44:52 EST ID:yGgK6aCs No.14308 Ignore Report Quick Reply
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>>14280

I totally get it now. We want to know the behavior around some point, disregarding what's actually happening at that point. However, we're perfectly fine with |f(x)-L| being zero. That's exactly where the asymmetry comes in. Thanks! No bump.


That background by Basil Ponderseg - Tue, 05 Aug 2014 17:26:04 EST ID:y0c2N06s No.14265 Ignore Report Reply Quick Reply
File: 1407273964691.png -(1064430B / 1.02MB, 842x464) Thumbnail displayed, click image for full size. 1064430
How does one make an animation like here in the background?
https://www.youtube.com/watch?v=kJ6hGs4fRmA
>>
Ebenezer Peggleman - Tue, 05 Aug 2014 20:48:19 EST ID:sPd/0oB/ No.14267 Ignore Report Quick Reply
I'm the guy who advised you to post on /math/.
You need to learn how to code to at least make the gif/jpg/png.

Learn a simple language on which you can draw stuff, like Processing. Draw simple stuff first (bouncing ball), then move on more complicated pictures, like the Mandelbrot set or 2D Perlin Noise.
Draw a square grid, then draw an hexagonal grid, then draw rainbows all over it, then change the coordinates to polar to get a spiral.

https://www.youtube.com/watch?v=0ifChJ0nJfM
http://shadertoy.com/
https://processing.org/examples/noisewave.html
http://processing.org/examples/tree.html
https://processing.org/examples/mandelbrot.html
>>
Rebecca Blythehood - Tue, 05 Aug 2014 22:36:57 EST ID:4glIJRAX No.14268 Ignore Report Quick Reply
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Are BP oil spill jokes still relevant?


cone surface area question by Molly Blackman - Thu, 31 Jul 2014 06:31:54 EST ID:Yu7owZ2i No.14254 Ignore Report Reply Quick Reply
File: 1406802714233.gif -(961964B / 939.42KB, 180x155) Thumbnail displayed, click image for full size. 961964
a water tank has the shape of a cone. the tank is 10 meters high and has a radius of 3 meters at the top. if the water is 5 meters deep ( in the middle), what is the area of the top of the water?

thanks guise

pic unrelated
>>
Archie Blickleshit - Thu, 31 Jul 2014 18:56:53 EST ID:atHzm3qN No.14255 Ignore Report Quick Reply
>>14254
Oh, c'mon. You're not even trying.
A=πr(r+h2+r2)

A = π3 (3+10*2+3*2)

If you only care about the surface area of the top ( a circle) you would just take the square of r (= 3) and multiply it by pi.
>>
Angus Ferrywell - Fri, 01 Aug 2014 03:08:22 EST ID:Yu7owZ2i No.14257 Ignore Report Quick Reply
>>14255
but the radius given is the maximum radius at the top, how do you calculate the radius of the top circle formed by the water when its 5 meters deep?
>>
Ian Sagglewick - Fri, 01 Aug 2014 11:37:04 EST ID:5quJ2CR5 No.14260 Ignore Report Quick Reply
>>14257
Its a cone, you know the radius at the top and bottom and the height. Its just lines bro.
>>
Jack Sizzlewodge - Sun, 03 Aug 2014 13:36:02 EST ID:8NZnQ0yA No.14262 Ignore Report Quick Reply
1407087362061.jpg -(24067B / 23.50KB, 292x327) Thumbnail displayed, click image for full size.
>>14257
Solve for the radius of the circle of the top of the water using similar triangles:
x/5=3/10
x=15/10=3/2

Solve for the area of the top of the water using the radius:
π(3/2)(3/2)=9π/4
>>
Fucking Bardridge - Mon, 04 Aug 2014 21:03:34 EST ID:uspvjvJI No.14263 Ignore Report Quick Reply
>>14257
Just think about the geometry of it in your head. The radius at the top of the cone is 3, and the radius at the bottom is 0 because it's just a point. The radius increases from 0 to 3 proportionally with the height increasing from 0 to 10, so if the water height is half of the maximum, then the radius is also half of the maximum.


I need to know the background knowledge of these subjects, for science! by Albert Pammlelock - Fri, 01 Aug 2014 00:08:57 EST ID:FOjl8NEa No.14256 Ignore Report Reply Quick Reply
File: 1406866137068.png -(624362B / 609.73KB, 1600x900) Thumbnail displayed, click image for full size. 624362
Hi, I am a guy who needs a refresher on certain topics on mathematics so I can work on these:

Sadly, I am not so sure if these would translate into their english counter parts, so I left them like this.
I am working on pre-calculus on coursera, though and it works well enough

Linear Algebra I:
Gruppen, Körper, Vektorräume, lineare Unabhängigkeit, Basis, lineare Abbildungen, Dualraum, Matrizen (elementare Zeilentransformationen, Rang, Invertierbarkeit, Inverse, ...), lineare Gleichungssysteme, Determinante


Linear Algebra:
Groups, Bodies, Vectorrooms, linear independency, Base, linear mapping, Dualroom, Matrices, linear equation system, determinants.


Analysis I:
ganze Zahlen, vollständige Induktion, reelle und komplexe Zahlen, Folgen, Grenzwert, Reihen, Stetigkeit, Differentialrechnung, Taylorreihe, Integralrechnung, elementare Differentialgleichungen
Comment too long. Click here to view the full text.
>>
Albert Pammlelock - Fri, 01 Aug 2014 03:52:38 EST ID:FOjl8NEa No.14258 Ignore Report Quick Reply
Oh shit, I worded it wrong.
I need the pre-requisites for it, just the pre-requisites
>>
Basil Crummerbure - Fri, 01 Aug 2014 04:26:30 EST ID:VLYpS252 No.14259 Ignore Report Quick Reply
>>14256
http://tutorial.math.lamar.edu/

viel glück
>>
Esther Chinningwater - Sat, 02 Aug 2014 11:52:45 EST ID:Gw2IN3ba No.14261 Ignore Report Quick Reply
>Am I on the right road?

So you're trying to teach this stuff to yourself? Why do you want to learn this? For linear algebra, you need calculus I and calculus II. For analysis, you need abstract vector spaces.


Quick question by Consumer Math - Tue, 29 Jul 2014 04:29:27 EST ID:BfGCwHN9 No.14252 Ignore Report Reply Quick Reply
File: 1406622567646.jpg -(785291B / 766.89KB, 2816x1880) Thumbnail displayed, click image for full size. 785291
If I were to finance a bike at $520 for 12 months, what would my annual percentage rate be if the finance charge is at $35.67?
>>
Lydia Clibbledale - Thu, 31 Jul 2014 04:03:52 EST ID:4UT2KZmc No.14253 Ignore Report Quick Reply
520/35.67=14.4780786815 a month


Greetings /π/ by Charles Murdworth - Sun, 20 Jul 2014 05:35:27 EST ID:OWPvoCXf No.14222 Ignore Report Reply Quick Reply
File: 1405848927891.jpg -(79370B / 77.51KB, 911x838) Thumbnail displayed, click image for full size. 79370
I'm here with a burning question, and I'm a dipshit and this shit flies right above my head.
Let's say what if this guy actually figured out a valid formula for how frequencies interact.

https://www.youtube.com/watch?v=jVATlX4XKMk&list=PL0838D67BB8E0396C


So I will paraphrase my story. Basically, I have a jar of mushroom vodka currently fermenting in the corner of my room.
To keep the jar cool I have a small fan running.
The fan despite being cheap is a fast and efficient beast with a powerful motor.
I have verified that the motor's vibration is vibrating precisely at 459 HZ G#

>Question
So because the alleged effects of frequencies on our brains I have to assume that the binaural effect created by my room fan in conjunction with remarkably wide room resonance
is going to be doing something to my brain, and Maybe this is an opportunity to test the so called theory in analog manner.
I'll post a diagram to show exactly how this room effect is achieved. I tried to get an audio recording of it, but now luck.. maybe if I had a set of sensitive binaural mics.
Comment too long. Click here to view the full text.
1 posts omitted. Click Reply to view.
>>
William Paddlenutch - Tue, 22 Jul 2014 14:47:48 EST ID:Gw2IN3ba No.14228 Ignore Report Quick Reply
1406054868200.jpg -(25192B / 24.60KB, 390x390) Thumbnail displayed, click image for full size.
I seriously hope you're trolling OP. Also, wtf is mushroom vodka?

This is now a timecube thread.

http://www.timecube.com/

http://youtu.be/Tn2UCqL5qyo
>>
Nigel Murdville - Tue, 22 Jul 2014 16:02:10 EST ID:gU9kqsUV No.14229 Ignore Report Quick Reply
1406059330710.jpg -(62107B / 60.65KB, 640x480) Thumbnail displayed, click image for full size.
>>14228
what am i reading here
>>
William Paddlenutch - Tue, 22 Jul 2014 19:09:07 EST ID:Gw2IN3ba No.14231 Ignore Report Quick Reply
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>>14229
>what am i reading here

A paradigm shift that will rock your world to its cubic core. You are beginning to understand that everything you were ever taught before the realization of cubic time amounts to nothing!
>>
Molly Worthingbury - Wed, 23 Jul 2014 02:31:55 EST ID:v2qInvsx No.14235 Ignore Report Quick Reply
>>14228
YOU ARE NOT THE WISEST HUMAN GENE RAY, YOU FILTHY WORD ANIMAL
>>
Hugh Turveyhall - Thu, 24 Jul 2014 03:02:04 EST ID:lx6v5XWF No.14244 Ignore Report Quick Reply
"a set of sensitive binaural mics."

Do you mean "two microphones"?
Or, if the motor's vibration at "precisely" 459hz doesn't change, "one microphone"? You do realize that "how frequencies interact" is addition, right?


is math real by Ernest Nopperbury - Tue, 03 Jun 2014 16:57:49 EST ID:Uq/TU4om No.14060 Ignore Report Reply Quick Reply
File: 1401829069682.gif -(1375B / 1.34KB, 60x60) Thumbnail displayed, click image for full size. 1375
do discrete systems even exist outside of conceptual renderings?
I guess our number system came out of counting things by orders of ten, using fingers to represent whatever was being counted, but the map is not the territory and information doesn't translate into number of fingers so easily.. In a digital world, things stick to the program, but I can't really tell if reality is quantifiable, if you know what I mean.
2 posts omitted. Click Reply to view.
>>
Matilda Wankinnure - Sat, 05 Jul 2014 22:10:50 EST ID:kFCSHfPa No.14174 Ignore Report Quick Reply
>do discrete systems even exist outside of conceptual renderings?

/pss/ fag here. I think we can take a few different tacks with this.

First: how is it that we can conceive of discrete systems if none exist in nature? For that matter, what, exactly, is going on when we conceive of a discrete system? Does said system exist in our brains somehow?

Secondly: mathematics isn't all discrete. There are mathematical continua. Couldn't those be real?
>>
Martha Drummleman - Wed, 16 Jul 2014 02:37:20 EST ID:jEbtLayo No.14216 Ignore Report Quick Reply
Do our thoughts exist physically? Surely our thoughts are some kind of representation of the physical world. But are the two the same thing?
>>
Charlotte Grimridge - Thu, 17 Jul 2014 20:23:26 EST ID:Dn4zhXKX No.14218 Ignore Report Quick Reply
>>14174
There are quite a few Pythagoreans who talk about pi as an algorithm, rather than a number, and who think discrete math is true to reality and continuous math is conceited. Doron Zeilberger, for one.

Seems to go hand in hand with digital physics and universe/brain-as-computer doctrine. Personally, I don't care about whatever's the most empirical metaphysics; thought and experience are continuous.
>>
Archie Wazzletere - Sat, 19 Jul 2014 04:01:08 EST ID:d7wWJNnk No.14219 Ignore Report Quick Reply
In mathematics there are structures and theories. Structures are things like the natural numbers or real numbers, and theories are the collection of statements deduced from axioms using deduction rules. Mathematics attempts to describe these structures using theories, but due to the incompleteness theorems we know that we will never be able to know all the true facts about, say, the natural numbers. But it's clear that natural numbers exist (as counting objects) and the continuum exists as well (as distances between objects). The theories on the other hand, that attempt to describe these structures, are purely human constructs that optimistically try to approach the truth about the structures.

I like to think of mathematics sort of like a biography about a real person. The subject really exists as a corporeal thing (structures), but the biography is a human construct that tries to tell the true facts about the subject. It should be clear that a biography could never tell every little fact about a person, but if it's a really great person they're worth writing about even if you can't tell it all! What makes the biography of mathematics special is that it is a biography of the most fundamental concepts of existence.

In short, both discrete and continuous things are real. Our descriptions of them in mathematics cannot encompass all the truth about them, but what they are about is fundamentally real.

>>14218

I've heard of these people being called constructivists rather than pythagoreans. Or finitists, like zeilberger. They don't deny the possibility of continuity, the rationals are continuous and none of these guys would deny the existence of fractions. What they stand against is the notion of a "completed" infinity, the idea of being able to produce any infinite ordinal is a good point but I think is an over-reaction to a misperception of infinity in the public.
>>
Shit Smallman - Thu, 24 Jul 2014 02:50:21 EST ID:VbY4tW0M No.14243 Ignore Report Quick Reply
>>14219
Math, at least pure math, consists entirely of induction and rationalism. Any math proof you read is a priori which is fucking insane.


Simple Algebra Question by Barnaby Hadgeville - Tue, 15 Jul 2014 15:01:32 EST ID:qCDKBx4v No.14213 Ignore Report Reply Quick Reply
File: 1405450892751.jpg -(4806B / 4.69KB, 328x70) Thumbnail displayed, click image for full size. 4806
Can someone explain in a very verbose way how the first term = the second term in this image?
>>
Shit Nicklewater - Tue, 15 Jul 2014 15:26:08 EST ID:Fj/YvlCk No.14214 Ignore Report Quick Reply
Yesh. Remember that a root is the same as a (fractional) power. That is:
(a+b)^2 =/= a^2+b^2 but
(ab)^2 = a^2b^2

You can factor out 4 below: sqrt( 4 * (-x^2-x) ) which is sqrt(4)*sqrt(-x^2-x)
And sqrt(4) = 2 which cancels out the 2 above.

Goddamn I wish this website supported latex.
>>
Jarvis Munningman - Tue, 15 Jul 2014 20:33:17 EST ID:qCDKBx4v No.14215 Ignore Report Quick Reply
Thank you sir. I think I'll just keep this 1 thread for all my basic questions.
>>
Hugh Turveyhall - Thu, 24 Jul 2014 02:48:19 EST ID:lx6v5XWF No.14242 Ignore Report Quick Reply
(a^m * b)^1/m = (a^m)^1/m * b^1/m = a * b^1/m


Business Math by ConfusedSoul - Wed, 23 Jul 2014 00:12:37 EST ID:BfGCwHN9 No.14233 Ignore Report Reply Quick Reply
File: 1406088757916.png -(303224B / 296.12KB, 500x500) Thumbnail displayed, click image for full size. 303224
I, for the life of my cannot figure this solution out. This is the last question on my study guide and I am totally stumped:
On April 1st, the unpaid balance in an account was $174. A payment of $70 was made on April 8th. On April 26 a $26.00 purchase was made. The interest rate per month was 1.75% per month of the average daily balance. Find the finance charge and new balance at the end of April.
2 posts and 1 images omitted. Click Reply to view.
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Whitey Billingshaw - Wed, 23 Jul 2014 10:19:31 EST ID:2aEkBtv5 No.14237 Ignore Report Quick Reply
((7(174)+18(104)+5(130))/30)(0.0175)+130=132.18

Yes? No?
>>
Fucking Ponderseg - Wed, 23 Jul 2014 10:29:38 EST ID:GT+uOqbr No.14238 Ignore Report Quick Reply
"Business Math" is just story problems from 3rd grade. Math with a narrative should not be considered a separate type of math. Whoever thought of this needs to die.
>>
Molly Worthingbury - Wed, 23 Jul 2014 17:23:12 EST ID:v2qInvsx No.14239 Ignore Report Quick Reply
>>14236
Sorry I was a dick. I'm assuming the "finance charge" is the interest charged at the end of the month.

To find the interest, you need to know the average daily balance. There were 8 days at $174, 17 days at $104, and 4 days at $78. That's an average of $115.73. So the finance charge is .0175*115.73. And the balance is 104-the finance charge.
>>
Molly Worthingbury - Wed, 23 Jul 2014 17:30:25 EST ID:v2qInvsx No.14240 Ignore Report Quick Reply
>>14239
Oh shit, nevermind. It's a credit card.

There were 8 days at $174, 17 days at $104, and 4 days at $130. That's an average of $123. So the finance charge is .0175*123. And the balance is 130 plus the finance charge.
>>
Hugh Turveyhall - Thu, 24 Jul 2014 02:38:26 EST ID:lx6v5XWF No.14241 Ignore Report Quick Reply
Break it down into smaller problems.
First, find the average daily balance.

So the initial balance is $174, and this balance lasts for 7 days.
On the 8th, $70 is paid off, and so the new balance of $174 - $70 lasts for 18 days.
On the 26th, a $26 purchase is made, so the new balance is $174 - $70 + $26, and this lasts through the end of the month.

Thirty days hath September, April, June, and November, so that balance lasts for 5 days.

So the average daily balance is:
[ 7 * 174 + 18 * (174 - 70) + 5 * (174 - 70 + 26) ] / 30

"Cent" means 100 (century, centurion, 100 cents in a dollar), and "per" means "divide", so "per cent" means "divide this by 100"

( 1.75/100 )
Comment too long. Click here to view the full text.


Get X Y by Matilda Daggleville - Mon, 21 Jul 2014 21:33:34 EST ID:Bbuuretd No.14226 Ignore Report Reply Quick Reply
File: 1405992814795.png -(15867B / 15.50KB, 439x305) Thumbnail displayed, click image for full size. 15867
If i have a angle to an object and i know the distance to it. how can i know its coordinates?
made in geogebra
>>
William Paddlenutch - Tue, 22 Jul 2014 04:30:42 EST ID:Gw2IN3ba No.14227 Ignore Report Quick Reply
(r*cos(theta), r*sin(theta)) where r is the distance and theta is the angle

http://en.wikipedia.org/wiki/Polar_coordinate_system#Converting_between_polar_and_Cartesian_coordinates
>>
Nathaniel Woshshaw - Tue, 22 Jul 2014 18:40:14 EST ID:yaOOvKGH No.14230 Ignore Report Quick Reply
>>14227
That's assuming the observer is in (0,0) of course.
>>
James Gerrynut - Tue, 22 Jul 2014 23:26:00 EST ID:Vq7cxA7H No.14232 Ignore Report Quick Reply
>>14230
thanks m8


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