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javascript by Lydia Gudgedale - Sat, 12 May 2018 20:10:25 EST ID:r5si74OP No.37533 Ignore Report Quick Reply
File: 1526170225292.png -(863168B / 842.94KB, 1452x2208) Thumbnail displayed, click image for full size. 863168
just sharing this enjoyable picture image with a text post
>>
Rebecca Blebblelock - Sat, 12 May 2018 23:20:04 EST ID:lP7MCiRB No.37536 Ignore Report Quick Reply
1526181604017.gif -(34345B / 33.54KB, 600x450) Thumbnail displayed, click image for full size.
>>37533
Yes
>>
Isabella Gimmerhall - Sun, 13 May 2018 06:14:36 EST ID:Xm/W+3lL No.37537 Ignore Report Quick Reply
I liked that. Thanks for sharing, OP.
>>
Doris Cradgelot - Fri, 18 May 2018 03:26:20 EST ID:+joVuqaF No.37543 Ignore Report Quick Reply
1526628380219.jpg -(46819B / 45.72KB, 330x512) Thumbnail displayed, click image for full size.
That behavior's not actually a bug. Loose equals (`==`) just means that type coercion is allowed. Section 11.9.3 of the ES5 specification says if both things being compared have the same type, they're compared via identity; if they have different types, perform the following steps are until both things have the same type (then they're compared via identity).

for x == y:

2) If x is null and y is undefined, return true.

3) If x is undefined and y is null, return true.

4) If Type(x) is Number and Type(y) is String, return the result of the comparison x == ToNumber(y).

5) If Type(x) is String and Type(y) is Number, return the result of the comparison ToNumber(x) == y.

6) If Type(x) is Boolean, return the result of the comparison ToNumber(x) == y.

7) If Type(y) is Boolean, return the result of the comparison x == ToNumber(y).

8) If Type(x) is either String or Number and Type(y) is Object, return the result of the comparison x == ToPrimitive(y).

9) If Type(x) is Object and Type(y) is either String or Number, return the result of the comparison ToPrimitive(x) == y.

So according to rule 4: 0 == "0" reduces to 0 == Number("0") which reduces to 0 == 0 which is true.

And according to rule 8: 0 == [] becomes 0 == [].valueOf(). Since [].valueOf() doesn't return a primitive (it returns an array, which is an object), the expression becomes 0 == [].toString() or 0 == "". Rule 4 is invoked: 0 == Number("") resolves to 0 == 0, which is true.

"0" == [] does not work because the rules for loose equals coerce it into "0" == "" which is unquestionably false.

If you don't like type coercion, stop comparing things of different types, or use strict equals, which does not coerce types at all.
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Shit Fanfield - Fri, 01 Jun 2018 20:05:49 EST ID:+t8dQYkO No.37550 Ignore Report Quick Reply
Eso marea
>>
Hannah Ballyspear - Sat, 02 Jun 2018 10:04:55 EST ID:9QSfnS0r No.37554 Ignore Report Quick Reply
>>37543
Worse of all
[] == {}
false
>>
Hannah Ballyspear - Sat, 02 Jun 2018 10:09:46 EST ID:9QSfnS0r No.37555 Ignore Report Quick Reply
>>37554
That said I don't use the equality operator in most cases.

Where type coercion is useful are (sadly neeccesary santiy checks like)

if (thing && otherthing && thing[otherthing] && thing[otherthing].value ) {
// use thing[otherthing].value
}
>>
Angus Clommermud - Tue, 26 Jun 2018 16:05:30 EST ID:lP7MCiRB No.37570 Ignore Report Quick Reply
Just sharing this enjoyable link of a Markov chain trained on the Puppet documentation and the assorted works of H. P. Lovecraft.

Excerpt:
“At length they emerged on a muddy road to find the server, how to authenticate to it, and more.”

http://thedoomthatcametopuppet.tumblr.com/?
>>
Fanny Gunnerstock - Sat, 30 Jun 2018 07:54:12 EST ID:lP7MCiRB No.37571 Ignore Report Quick Reply
1530359652515.png -(729B / 729bytes, 135x34) Thumbnail displayed, click image for full size.
> Haskell


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