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Somebody please explain interfaces in C++

- Thu, 22 Feb 2018 15:54:59 EST kBelsIZm No.37445
File: 1519332899121.jpg -(165557B / 161.68KB, 1280x960) Thumbnail displayed, click image for full size. Somebody please explain interfaces in C++
I have a question.
I've done something similar to the example on this page.

What they've got there is a virtual class that's called Shape. And then a load of derived classes called things like Rectangle and Circle etc.

Then the go
Rectangle rectangle = new Rectangle();

What I can't see is a way to declare a variable of type Shape. I don't care if that winds up a Rectangle or Circle because they both will implement the interface. How can I do the following?

Shape shape = methodThatWillGiveMeRectOrCircle();

My compiler can't compile that method. It says:
> error: return type 'Shape' is an abstract class
Jarvis Wesslelure - Thu, 22 Feb 2018 23:07:30 EST 8hwK1pxu No.37447 Reply
You have to use pointers.
Shape* shape = methodThatWillGiveMeRectOrCircle();
cout << "Totalarea: " << shape->getArea() << endl;
delete shape;
Martha Drellyway - Fri, 23 Feb 2018 04:51:38 EST kBelsIZm No.37448 Reply
That did the trick, thanks for pointing that out.
Can you explain to me why a pointer works here?
From what I understand, an int* can't just be assigned to a char* or void* without being explicitly cast so why is this different?
Rebecca Dumbleshit - Fri, 23 Feb 2018 23:50:53 EST 8hwK1pxu No.37450 Reply
That's just how polymorphism in C++ works.

A Rectangle IS A Shape so it can always be safely cast implicitly.
While a Shape may not necessarily be a Rectangle so it has to be explicitly cast.
Wesley Furringnet - Sat, 24 Feb 2018 01:37:47 EST BW3MomrQ No.37451 Reply
You might be able to use references here too, but if that works then it's only because references are just pointers with nice syntax under the hood.

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